[프로그래머스]Lv.0 리스트 자르기C# (linq 포함)

https://school.programmers.co.kr/learn/courses/30/lessons/181897

프로그래머스

소스코드1

using System;
using System.Collections.Generic;
using System.Linq;
public class Solution {
    public int[] solution(int n, int[] slicer, int[] num_list) {
            List<int> answer =new List<int>();

            int a = slicer[0];
            int b = slicer[1];
            int c = slicer[2];

            switch (n)
            {
                case 1:
                    for (int i = 0; i <= b; i++)
                        answer.Add(num_list[i]);
                    break;
                case 2:
                    for (int i = a; i < num_list.Length; i++)
                        answer.Add(num_list[i]);
                    break;
                case 3:
                    for (int i = a; i <= slicer[1]; i++)
                        answer.Add(num_list[i]);
                    break;

                case 4:
                    for (int i = a; i <= b; i += c)
                        answer.Add(num_list[i]);
                    break;
            }
            return answer.ToArray();
    }
}

소스코드2

using System;
using System.Collections.Generic;
using System.Linq;
public class Solution {
    public int[] solution(int n, int[] slicer, int[] num_list) {
            List<int> answer =new List<int>();

            int a = slicer[0];
            int b = slicer[1];
            int c = slicer[2];
        
           if (n == 1)
                return num_list.Where((x, index) => index >= 0 && index <= b).ToArray();
            else if (n == 2)
                return num_list.Where((x, index) => index >= a && index < num_list.Length).ToArray();
            else if (n == 3)
                return num_list.Where((x, index) => index >= a && index <= b).ToArray();
            else if (n == 4)
                return num_list.Where((x, index) => index >= a && index <= b).Where((x, index) => index % c == 0).ToArray();
            return null;
    }
}